Submitted by Martinjg_ge t3_123eqnz in askscience
Since you're splitting water you get both, but i'd imagine they be split at the same place. I don't mean "why is h2 at the cathode and o2 at the anode", I mean, the water molecule is split somewhere, and then the oxygen and hydrogen just... travel to the place where there be their charge? Are the water molecules split between the anode and cathode and just travel up at them? If they travel to the opposite end, why don't we see bubbles anywhere but the electrodes?
ECatPlay t1_jdvu65s wrote
>I mean, the water molecule is split somewhere
I think you are getting hung up thinking of it as the water molecule. Keep in mind water is a sea of molecules, with a lot of exchanges going on:
H2O ⇌ H^+ + OH^-
OH^- + H2O ⇌ H2O + OH^-
H^+ + H2O ⇌ H3O^+
H3O^+ + H2O ⇌ H2O + H3O^+
So when the hydrogen in a water molecule near the cathode accepts an electron to start forming H2, the remaining OH^- doesn't itself have to migrate to the anode to be oxidized to O2. It just has to exchange with a neighboring water molecule's hydrogen, so now there is a new OH^- a little closer to the anode. So you end up with H^(+)'s being transferred along through the aqueous medium, something like a bucket brigade, to keep supplying H^+ to the cathode and OH^- to the anode, but not necessarily the same H or O in each transfer.
H3O^+ + H2O + H2O + H2O ->
H2O + H3O^+ + H2O + H2O ->
H2O + H2O + H3O^+ + H2O -> -> ->
H2O + H2O + H2O + OH^- ->
H2O + H2O + OH^- + H2O ->
H2O + OH^- + H2O + H2O -> -> ->
In effect you have H^(+)'s being passed along in one direction, and OH^(-)'s being passed along in the other direction.
(Edit: italicized the initial H and O)