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zimonitrome t1_iwbst8p wrote

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maybelator t1_iwbxutj wrote

The Huber loss encourages the regularized variable to be close to 0. However, this loss is also smooth: the amplitude of the gradient decreases as the variable nears its stationary point. In consequence, it will have many coordinates close to 0 but not exactly. Achieving true sparsity requires thresholding which adds a a lot of other complications.

In contrast the amplitude of the gradient of the L1 norm (absolute value in dim 1) remain the same no matter how close it gets to 0. The functional has a kink (the subgradient contains a neighborhood of 0). In consequence, if you used a well-suited optimization algorithm, the variable will have true sparsity, i.e. a lot of exact 0.

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zimonitrome t1_iwc14i5 wrote

Wow thanks for the explanation, it does make sense.

I had a pre-conception that all optimizers dealing with any linear functions (kinda like L1 norm) still produce values close to 0.

I can see someone disregarding tiny values when using said sparsity (pruning, quantization) but didn't think that it would be exactly 0.

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