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Lithuim t1_j2adeje wrote

The moon’s (or any object’s) gravity is directly proportional to its mass, so yes.

If the moon was a hollow paper mache sphere you wouldn’t get nearly as much tidal effect here on Earth.

The force between the two is G(m1 x m2)/r^2

The moon does exert tidal drag on the Earth, slowly sapping rotational energy and making days longer.

The much more massive Earth has done the same to the moon, dragging it so hard that it’s now permanently fixed with one side facing Earth.

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nekokattt t1_j2afgd8 wrote

(where G is a gravitational constant, 6.67430x10^-11 ; m1 is the mass of the first object; m2 is the mass of the second object; and r is the distance between them, i.e. the radius of the orbit).

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Tegasauras OP t1_j2agbr9 wrote

That makes things much clearer, thank you. Would you be able to point me in a reference of algebra ( let’s start from the basics! ) to start understanding this also?

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Lithuim t1_j2ahfuu wrote

Any middle school algebra textbook I guess. The gravitation equation is thankfully very simple.

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