Submitted by AnOriginalMan405 t3_zytxm2 in space
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Submitted by AnOriginalMan405 t3_zytxm2 in space
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A note on spaghettification: For very large black holes, of which TON 618 is certainly one, you can actually pass the event horizon and may not even know it. This is because gravity works according to the square of the distance to a mass, as such:
F = G( (m1*m2)/r^2 )
Where F is the force on an object, G is the gravitational constant, m1 and m2 are the masses in question (you and TON 618) and r is the distance between. So, the event horizon will be very far from the singularity and when you cross it say feet-first, the difference in force between your feet and your head will be minimal until you get much closer to the singularity.
From what I understand about it though, at the point you're inside the event horizon, collision with the singularity becomes inevitable. But could you move into a slowly decaying orbit near light speed and watch the rest of the universe go cold as TON 618 eventually evaporates and sets you free? I don't think we really know.
No.
Amateur theory here. Happy to be corrected.
You pass the event horizon and the entire rest of the universe occurs blueshifted indefinitely directly over you. Any event horizon, regardless of the mass, is uncrossable in a finite amount of time. The amount of time it takes for a black hole to evaporate is finite.
You become part of the black hole long enough to become its hawking radiation, and disperse your energy among the...well...
Void.
Nope. You only appear to be part of the event horizon to a distant observer. You actually travel to the center of the black hole and are crushed and die. It is inevitable because all paths inside a black hole flow to the center. It is actually impossible to not reach the center. Even if you change direction you reach the center. It is as inevitable as time itself. Trying to go out of the black hole is like going back in time and so is impossible.
You are confusing what a distant observer sees to what happens to you.
Is there not also an infinite amount of time passing in the universe above the event horizon, instantly evaporating the entire black hole according to the internal observer?
Or do black holes break causality?
No man, you fall in and you die. The black hole still is there. Sorry that is how it works.
Time is slowed for you and the black hole. So it will live on far far after it has crushed you into a pulp.
You are confusing reference frames. If your time is slowed, the black hole's time is slowed relative to an outside observer. So you are experiencing the same time. Not sure how it could age more quickly than you or more quickly than the outside observer when it is also experiencing time dilation.
Does this mean if you are a big baddie you can't hurl your enemies into a black hole?
Asking for a friend.
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First of all, there is no singularity. That is a mathematical object not a physical object. It represents where our math fails. Also you don't even have a complete picture because there are in fact multiple mathematical singularities inside a spinning black hole and it is far more complex than you are probably aware of. You have a novice interpretation of it.
Secondly, for you time is not slowed from your perspective. You pass towards the center of the black hole and reach it at a normal rate.
You would definitely die before the black hole does.
Spinning black holes (which they all are)... https://youtu.be/kIbP2Sg8y18
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Miss_Masquerade86 t1_j27va2x wrote
If I'm not mistaken, and I could be wrong so maybe other comments will correct it if I am, but I believe is relative. From your perspective time would be passing as normal and while you will immediately be spagehttified, your atoms will reach the singularity. Time would be distorted for those viewing it from far off.
Similarly for someone going near the speed of light, time will appear normal for them but for those viewing it from from you will be going very very slowly.